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get_loaded_extensions> <get_include_path
[edit] Last updated: Fri, 25 May 2012

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get_included_files

(PHP 4, PHP 5)

get_included_filesRetourne un tableau avec les noms des fichiers qui sont inclus dans un script

Description

array get_included_files ( void )

Retourne un tableau contenant les noms de tous les fichiers qui ont été ajoutés au script avec les fonctions include, include_once, require ou require_once.

Valeurs de retour

Retourne un tableau contenant les noms de tous les fichiers.

Le script en cours est considéré comme fichier inclus, il sera donc listé avec les autres fichiers dont il est fait référence avec include et les fonctions assimilées.

Les fichiers inclus ou requis plusieurs fois ne s'affichent qu'une fois dans le tableau retourné.

Historique

Version Description
4.0.1 En PHP 4.0.1 et inférieure, cette fonction supposait que les fichiers requis utilisait l'extension .php ; les autres extensions ne fonctionnaient pas. Par ailleurs, dans cette version, le tableau retourné par la fonction get_included_files() était un tableau associatif et ne reprenait que les fichiers ajoutés avec include et include_once.

Exemples

Exemple #1 Exemple avec get_included_files()

<?php
// Ce fichier est abc.php

include 'test1.php';
include_once 
'test2.php';
require 
'test3.php';
require_once 
'test4.php';

$included_files get_included_files();

foreach (
$included_files as $filename) {
    echo 
"$filename\n";
}

?>

L'exemple ci-dessus va afficher :

abc.php
test1.php
test2.php
test3.php
test4.php

Notes

Note:

Les fichiers inclus en utilisant la directive de configuration auto_prepend_file ne sont pas listés.

Voir aussi



get_loaded_extensions> <get_include_path
[edit] Last updated: Fri, 25 May 2012
 
add a note add a note User Contributed Notes get_included_files
donikuntoro at integraasp dot com 29-Aug-2011 03:32
This function aims to perform filtering of files that have been included :

<?php
function setIncludeFiles($arrayInc = array()){
   
$incFiles = get_included_files();
    if((
count($arrayInc)>0)&&(count($incFiles)>0)){
       
$aInt = array_intersect($arrayInc,$incFiles);
        if(
count($aInt)>0){
            return
false;
       }elseif(
count($aInt)<1) {
        foreach(
$arrayInc as $inc){
            if(
is_file($inc))
                include(
$inc);
            else{
                return
false;
            }
        }
       }   
    }else{
        return
false;
    }
}
?>

Usage :

<?php
$toBeInclude
= array('/data/your_include_files_1.php',
'/data/your_include_files_2.php',
'/data/your_include_files_3.php',
);
setIncludeFiles($toBeInclude);
?>

Return false if something goes wrong.
cleggypdc at gmail dot com 23-Jun-2008 09:47
If you want to get the relative path of an included file, from within itself use this function. If you ever have a include file thats path may not be static, this can save some time.

<?php
 
function get_current_files_path($file_name)
 {
  
//find the current files directory
  
$includes = get_included_files();
  
$path = "";
   for (
$i=0; $i < count($includes); $i++)
   {
    
$path = strstr($includes[$i], $file_name);
     if (
$path != false)
     {
      
$key = $i;
       break;
     }
   }
  
$path = str_replace(getcwd(), "", $includes[$key]);
  
$path = str_replace("\\", "/", $path);
  
$path = str_replace($file_name, "", $path);
  
$path = ltrim($path, "/");
  
   return
$path;
 }
?>
sam at consideropen dot com 29-May-2008 01:57
If you want to avoid the filepaths, just wrap get_included_files() inside preg_replace() to get rid of path info:

<?php
$filenames
= preg_replace("/\/.*\//", "", get_included_files());
?>
yarco dot w at gmail dot com 03-Jul-2007 08:27
If you have a MAIN php script which you don't want to be included by other scripts, you could use this function. For example:

main.php:
<?php
function blockit()
{
 
$buf = get_included_files();
  return
$buf[0] != __FILE__;
}

blockit() and exit("You can not include a MAIN file as a part of your script.");

print
"OK";
?>

So other script couldn't include main.php to modify its internal global vars.
indigohaze at gmail dot com 28-Aug-2006 10:30
Something that's not noted in the docs, if a file is included remotely and you do a get_included_files() in the include itself it will *not* return the document that included it.

ie:
test2.php (server 192.168.1.14):
<?php

include("http://192.168.1.11/test/test3.php");

?>

test3.php (server 192.168.1.11):

<?php

$files
= get_included_files();

print_r($files);
?>

returns:

Array ( [0] => /var/www/localhost/htdocs/test/test3.php )

Which means you can use get_included_files() to help intercept and prevent XSS-style attacks against your code.
RPaseur at NationalPres dot org 08-Mar-2006 08:04
As is often the case, YMMV.  I tried the __FILE__ and SCRIPT_FILENAME comparison and found this:

SCRIPT_FILENAME: /var/www/cgi-bin/php441
__FILE__: /raid/home/natpresch/natpresch/RAY_included.php

As an alternative:

count(get_included_files());

Gives one when the script is standalone and always more than one when the script is included.
keystorm :at: gmail dotcom 07-Sep-2004 02:08
As of PHP5, this function seems to return an array with the first index being the script all subsequent scripts are included to.
If index.php includes b.php and c.php and calls get_included_files(), the returned array looks as follows:

index.php
a.php
b.php

while in PHP<5 the array would be:

a.php
b.php

If you want to know which is the script that is including current script you can use $_SERVER['SCRIPT_FILENAME'] or any other similar server global.

If you also want to ensure current script is being included and not run independently you should evaluate following expression:

__FILE__ != $_SERVER['SCRIPT_FILENAME']

If this expression returns TRUE, current script is being included or required.

 
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