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mysql_field_flags> <mysql_fetch_object
[edit] Last updated: Fri, 17 May 2013

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mysql_fetch_row

(PHP 4, PHP 5)

mysql_fetch_rowLiefert einen Datensatz als indiziertes Array

Beschreibung

array mysql_fetch_row ( resource $result )

Liefert ein numerisch indizertes Array, das der geholten Zeile entspricht und bewegt den internen Datenatzzeiger vorwärts.

Parameter-Liste

Ergebnis

Das Ergebnis Ressource, das ausgewertet wird. Dieses Ergebnis kommt von einem Aufruf von mysql_query().

Rückgabewerte

Gibt ein numerisches Array von Zeichenketten zurück, das der gelesenen Zeile entspricht oder FALSE falls keine weiteren Zeilen vorhanden sind.

mysql_fetch_row() liefert einen Datensatz aus dem Anfrageergebnis mit der übergebenen Kennung. Der Datensatz wird als Array geliefert. Jedes Feld wird in einem Array-Offset abgelegt, der Offset beginnt bei 0.

Beispiele

Beispiel #1 Eine Zeile mit mysql_fetch_row() holen

<?php
$result 
mysql_query("SELECT id,email FROM people WHERE id = '42'");
if (!
$result) {
    echo 
'Konnte Abfrage nicht ausführen: ' mysql_error();
    exit;
}
$row mysql_fetch_row($result);

echo 
$row[0]; // 42
echo $row[1]; // der email Wert
?>

Anmerkungen

Hinweis: Diese Funktion setzt NULL-Felder auf den PHP Wert-NULL.

Siehe auch



mysql_field_flags> <mysql_fetch_object
[edit] Last updated: Fri, 17 May 2013
 
add a note add a note User Contributed Notes mysql_fetch_row - [8 notes]
up
1
mysql at polyzing dot com
9 years ago
It is probably worth pointing out that the array elements will actually be of type string, OR NULL if the field is null in the database.

Thus, either use a double equal comparison to look for empty or null

Or, use a triple equal comparison to be able to distinguish the two cases

e.g.

if ($field === '') echo "Empty, not NULL\n";

if ($field === NULL) echo "NULL\n";

if ($field == '') echo "Empty or NULL\n";
up
1
michael and then an at sign wassupy.com
10 years ago
to print an array, simply use print_r(array name)

like this:
    $myrow = mysql_fetch_row($result);
echo "<pre>";
print_r($myrow);
echo "</pre>";

this will output the array in a readable form, with the index, too. Don't forget the 'pre' tags or the output will be on a single line.
up
2
m dot s at programmers-online dot net
7 years ago
The following function to read all data out of a mysql-resultset, is may be faster than Rafaels solution:

<?
function mysql_fetch_all($result) {
   while(
$row=mysql_fetch_array($result)) {
      
$return[] = $row;
   }
   return
$return;
}
?>
up
1
ryhan_balboa at yahoo dot com
5 years ago
The following are the basic codes to get a specific row from the mysql db into a $row variable:

 
$query = "SELECT * FROM table";
$result = mysql_query($query);
$row = mysql_fetch_row($result);

And $row[0], $row[1] ... $row[n] are used to access those field values.

Does anyone know how I can add a new field to $row, so that the field count increases from n to n+1?

I have tried treating $row like an array, and tried array_push function, but didn't work.

Thanks.
up
0
a at simongrant dot org
11 years ago
Maybe worth pointing out that all the fields returned by this (and other?) calls are returned with type string. This had me puzzled for quite some time.
up
-1
sarciszewski at knights dot ucf dot edu
1 month ago
If you need to quickly just grab all of a particular column (for example, with a "SELECT DISTINCT a FROM x" query), this quick function will just slice through and fetch an array of the resultant values:
<?
function mysql_slice($query, $colNo=0) {
 
// Return an array of single columns
 
if(gettype($query) == 'string') {
   
$sql = mysql_query($query) or die(mysql_error());
  } else {
   
$sql = $query;
   
var_dump($query);
  }
 
$array = array();
  for(
$i = 0; $i < mysql_num_rows($sql); $i++) {
   
$array[] = mysql_result($sql, $i, $colNo);
  }
 
mysql_free_result($sql);
  return
$array;
}
?>
To use it:
<?
 
foreach(mysql_slice("SELECT DISTINCT field FROM table") AS $x) {
    echo
"{$x}\n";
 }
// OR
 
$array = mysql_slice("SELECT DISTINCT field FROM table");
 
var_dump($array);
?>
up
-2
jhulbert at redf dot com
3 years ago
Creates table from all db info:

<?php
$qry
= "SELECT * FROM exp_member_data";
$res = mysql_query($mem_qry);

function
mysql_fetch_all($res) {
   while(
$row=mysql_fetch_array($res)) {
      
$return[] = $row;
   }
   return
$return;
}

function
create_table($dataArr) {
    echo
"<tr>";
    for(
$j = 0; $j < count($dataArr); $j++) {
        echo
"<td>".$dataArr[$j]."</td>";
    }
    echo
"</tr>";
}

$all = mysql_fetch_all($res);

echo
"<table class='data_table'>";

for(
$i = 0; $i < count($all); $i++) {
   
create_table($all[$i]);
}

echo
"</table>";

?>
up
-2
larkitetto at gmail dot com
5 years ago
sry :) note now fixed:

<?php
$esi
=mysql_list_tables($db);$ris=mysql_fetch_row($esi);
//example: $db has >= 1 tabs
echo var_dump($ris);
//echoes only array(1). solution:
while($ris=mysql_fetch_row($esi)) echo $ris[0];
/*debug:
$ris=array("1st_tab"); ... $ris=array("n_tab");$ris=false;*/
while ($ris[]=mysql_fetch_row($esi));
//debug:$ris=array(array("1st_tab"), ... array("n_tab"));
echo $ris[n][0];//echo:"n_tab"
echo $ris[0][n];//echo:array | null
?>

hope it helps

 
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