ibase_errmsg
ibase_execute only return resource id not the actual result, you need to use ibase_fetch_row or ibase_fetch_object to retrieve actual result.
On the example above given by anthony
it should be like these
$dbh = ibase_connect ( $host, $username, $password ) ;
$stmt = 'SELECT * FROM "EMPLOYEE" WHERE "SALARY" = ? AND "DEPT_CD" = ? ;' ;
$prep = ibase_prepare ( $dbh, $stmt ) ;
$salary = Array ( "10000", "25000", "33000", "48000" ) ;
$dept_cd = 'SALES' ;
foreach ( $salary as $val ) {
$res = ibase_execute ($prep, $val, $dept_cd);
$taxForm[$val] = ibase_fetch_row ($res);
}
ibase_execute
(PHP 4, PHP 5)
ibase_execute — Ausführen einer vorbereiteten Abfrage
Beschreibung:
int ibase_execute
( int $query
[, int $bind_args
] )
Führt eine vorher per ibase_prepare() vorbereitete Abfrage aus. Dies ist effizienter als der Gebrauch von ibase_query(), sofern sie mehrere ähnliche Abfragen durchführen wollen, bei denen sich immer nur einige Parameter ändern.
<?php
$updates = array(
1 => 'Erik',
5 => 'Phillip',
7 => 'Ludwig'
);
$query = ibase_prepare("UPDATE FOO SET BAR = ? WHERE BAZ = ?");
while (list($baz, $bar) = each($updates)) {
ibase_execute($query, $bar, $baz);
}
?>
add a note
User Contributed Notesibase_execute
caveman
24-Jan-2003 06:18
24-Jan-2003 06:18
mclap at ulstu dot ru
08-Sep-2002 01:54
08-Sep-2002 01:54
For variable argument list in ibase_execute you can use folowing functions:
For PHP >= 4.0.4:
function db_execute($stmt,$data)
{
if(!is_array($data))
return ibase_execute($stmt,$data);
array_unshift($data,$stmt);
$rc=call_user_func_array('ibase_execute',$data);
return $rc;
}
For any version of PHP:
function db_execute($stmt,$data)
{
if(!is_array($data))
return ibase_execute($stmt,$data);
$params = array();
while( list($k,$v) = each($data) )
$params[$k] = '$data['.$k.']';
eval('$rc=ibase_execute($stmt,'.join(',',$params).');');
return $rc;
}